Physics, asked by minterseeker3142, 2 days ago

An object of mass 50 kg is accelerated uniformly from a velocity of 2m/s to 4m/s in
6 s. Find the magnitude of force exerted on the objec

Answers

Answered by SwarajBose
1

Answer:

16.67 Newton (Approximately)

Explanation:

Initial velocity = u = 2 m/s, Final velocity = v = 4 m/s

Change in velocity = v-u = (4-2)m/s = 2 m/s and this change occurs in 6 sec = t

Acceleration = Rate of change in velocity

=\frac{v-u}{t}=\frac{2}{6}=\frac{1}{3}m/s^2

Force = Mass*Acceleration

Force = 50*\frac{1}{3}=\frac{50}{3}=16.67Newton

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