An object of mass 50kg is released from the height of 2000m,what will be height of object after 20s?
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Answer:
0 m.
Explanation:
Initial Velocity = 0 m/s
Acceleration = 10 m/s^2
Time = 20 s
Distance Covered = ut + 1/2gt^2 = 1/2 × 10 × 20 × 20 m = 2000 m
The object will cover 2000 m in 20 s. Also, it was thrown from an altitude of 2000m. So, its height will be 0 m.
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