Question

An object of mass 5kg and moving with an initial velocity 10m/s is acted on by a force for
6 seconds. Its velocity changes to 20m/s. Find the magnitude of the force acting on the
object.

Answer 1

Answer:

Hi

Explanation:

$\huge{\underline{\mathtt\red{Answer:-}}}$

$\longrightarrow$ $\bf\bold{\mathtt\blue{M}}$ = $\bf\bold{\mathcal\green{5 \: Kg}}$

$\longrightarrow$ $\bf\bold{\mathtt\blue{U}}$ = $\bf\bold{\mathcal\green{10 \: M/s}}$

$\longrightarrow$ $\bf\bold{\mathtt\blue{V}}$ = $\bf\bold{\mathcal\green{20 \: M/s}}$

$\longrightarrow$ $\bf\bold{\mathtt\blue{T}}$ = $\bf\bold{\mathcal\green{6 \: secs}}$

$\therefore$ $\bf\bold{\mathcal\purple{According \: to \: question:-}}$

$F = ma$

$F = m×(v-u/t)$

$F = 5×(20-10/6)$

$F = 5×10/6$

$F = 50/6$

$F = 8.33N$

$\therefore$ $\bf\bold{\mathcal\pink{The \: Force \: acting \: on \: object \: is \: 8.33N}}$