An object of mass 5kg falls from rest through a vertical displacement of 20m. It reached the ground with a velocity of 10m/s. What is the work done by air Resistance?
answer is -759J pls provide the steps
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Explanation:
From work energy theorem work done by weight + work done by air =ΔKE=ΔKE
Wair=ΔKE−W(weight)Wair=ΔKE−W(weight)
=1/2mv^2−mgh
=1/2×5×(10)^2−5×10×20
=−750J
:)
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