An object of mass 5kg falls from rest through a vertical distance of 20m and acquires a velocity of 10m/s the work done by the push of air on the object is( g=10m/s)
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@Physics GuruDev
From work energy theorem
Work done by weight + work done by air=ΔKE=ΔKE
Wair=ΔKE−W(weight)Wair=ΔKE−W(weight)
=12=12mv2−mghmv2−mgh
=12=12×5×(10)2−5×10×20×5×(10)2−5×10×20
=−750J
From work energy theorem
Work done by weight + work done by air=ΔKE=ΔKE
Wair=ΔKE−W(weight)Wair=ΔKE−W(weight)
=12=12mv2−mghmv2−mgh
=12=12×5×(10)2−5×10×20×5×(10)2−5×10×20
=−750J
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