An object of mass 5kg is accelerated uniformly from a velocity of 4m/s to 8m/s in 8s. calculate the initial and momentum of the magnitude of force of attraction of force exerted on the object.
Answers
Answered by
4
As we know p=mv
Pi=5kg÷×4m/s= 20kgm/s
Pf=5kg×8kgm/s
So F=∆p/∆t
=40-20/8=10/4
So force is 10/4
Similar questions