Question

An object of mass 5kg is at rest on a horizontal surface and is applied force of 10N for 5seconds what is the acceleration at 3sec, 7sec and 8sec?

Answer 1

☆Answer☆

v=13m/s

☆Explanation ☆

Given ,

Mass = 5kg .

t 1 = 2s

Intial velocity = 3m/s

Final velocity = 7m/ s.

t2 = 5s

So,

$a = > \frac{(v - u)}{t} = \frac{(7 - 3)}{2} = 2m \: s {}^{2}$

So the magnitude of the applied force is 10N

And the final velocity after 5s is v

So,

v=u+at

v=3+2×5

v=13m/s

The final velocity after 5s is 13m/s