Question

An object of mass 5kg is attached to the hook of a spring balance and the balance is suspended
vertically from the roof of a lift. The reading on the spring balance when the lift is going up with an acceleration of 0.25 m/s2 is
1) 55.25 N
2) 48.75 N
3) 52.75 N
4) 51.25 N
​

Answer 1

Answer:

51. 25 N

Explanation:

w

=

m

(

g

+

a

)

=

5

(

10

+

0.25

)=

5

×

10.25

=

51.25

N

Answer 2

The answer is attached.