Question

An object of mass 5kg is moving with a velocity of 10m/s .A force is applied so that in 20s it attains a velocity of 25m/s .What is the force applied on that object?(Ans:5N )

Answer 1

mass of object=5kg
initial velocity=10 m/s
final velocity=25m/s
time of impact of force=20 s
so,
according to newton's II law of motion:-
F=ma
a can be written as (v-u/t)
then,
5 × (v-u/t)
5 × (25-10/20)
so,
5×15/20
5×3/4
15/4 it equals to 3.75 N
hope it helps

Answer 2

Answer:

5N

Explanation:

$\tt \boxed{{F = M \times A}} [/tex}</p><p></p><p></p><p></p><p>[tex] \tt \blue{Given}$

Mass = 5kg

Initial velocity(u) = 10 m/second

Final velocity(v) = 25m/s

Time elapsed = 20 seconds

$\tt \green{ \boxed{Acceleration = \frac{(v - u)}{time}}}$

$\implies \tt \: \frac{25 -10(m {s}^{ - 1)} }{20(s)}$

$\implies \tt \: \frac{15m {s}^{ - 1} }{20s}$

$\implies \: 0.75 {ms}^{ - 2}$

Force = M×A

Force = 5kg × 0.7ms^-2

Force = 3.75 N