Question

An object of mass 5kg is moving with a velocity of 10m/s. A force is applied so that in 15 sec. It attains a velocity of 25m/s. What is the force applied on the object.

Answer 1

Answer:

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Explanation:

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Given Data:-

mass= 5kg

Initial velocity= 10 m persecond

Final Velocity= 0

Time= 2s

Required:-

F=?

Solution:-

First of all. To find acceleration we use first equation of motion.

a= vf - vi/ t

a= -5 m persecond square

Now Using Newton's second law of motion.

F= ma

F= -25N. The negative sign indicate that the force required to stop the body would be opposite to direction of the body.

Answer 2

Required Answer:

Given:

• Initial velocity (u) = 10m/s
• Final velocity (v) = 25m/s
• Mass of the object (m) = 5kg
• Time taken (t) = 15 sec

To calculate:

• Force applied on the object.

Calculation:

We know that,

• F = ma

Where,

• F = force = (to be calculated)
• m = mass = 5kg
• a = acceleration = ?

So, firstly we need to calculate acceleration:

By using the first equation of motion:

• v = u + at

→ 25 = 10 + ( a × 15 )

→ 25 = 10 + 15a

→ 15a = 25 - 10

→ 15a = 15

→ a = $\dfrac{15}{15}$

→ a = 1m/s²

Now,

• F = ma

→ F = 5 × 1

→ F = 5 N [Ans...]

Therefore,force applied on the object is 5 Newton.

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More information!

Equations of motion:

• v = u + at
• s = ut + ½at²
• v² – u² = 2as

Where,

• ★ v = final velocity = m/s
• ★ u = initial velocity = m/s
• ★ a = acceleration = m/s^2
• ★ s = distance/displacement = m
• ★ t = time = sec

Remember that!

• When a body starts from rest, its initial velocity is 0.
• When a body comes to stop or applies breaks, its final velocity is 0.

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