Question

An object of mass 5kg is moving with a velocity of 10ms-1 a force is applied so that in 20s it attains a velocity of 25ms-1 what is the force applied on the object

Answer 1

Force=mass×acceleration, acceleration=(change in velocity)/time interval

Initial velocity=10m/s

Final velocity=25m/s

Time interval=20s

Therefore, acceleration=(25-10)/20

=0.75m/s^2

Force=mass×acceleration

=5×0.75

=3.75N

Answer 2

Answer:

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Apply equation of kinematic

v=u+at

Acceleration, a=$\frac{v - u}{t}$

=$\frac{25 - 10}{20}$

=0.75m${s}^{ - 2}$

Force= mass x acceleration

F=5×0.75=3.75N

Hence, force is 3.75N