Physics, asked by dheerubaihambhani, 1 year ago

an object of mass 5kg is moving with a velocity of 10ms.a force is applied so that in 20seconds it attains a velocity of 25's. what is the force applied on the object?

Answers

Answered by sivaprasad2000
16
Initial velocity = u = 10 m/s

Final velocity = v = 25 m/s

time taken = t =20 s

From the equation v = u + at

a =  \frac{v-u}{t}  \frac{25-10}{20} =0.75 m/s^{2}

F = ma = 5 x 0.75 = 3.75 N




sivaprasad2000: Mark me as the brainliest
Answered by puransbohra975
13
Initial velocity u = 10m /s
final velocity v =25 m/s
time t=20 s
acceleration = v-u / t
25-10/20
3/4
Force= mass ×velocity
= 5×3/4 =3•75
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