An object of mass 5kg is moving with a velocity of 10ms. A force is applied so that in 20s , it attains a velocity of 25ms.what is the force applied on the object?
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Answered by
12
acceleration = (V-U)/t
= (25-10)/20
= 15/20 = 3/4 ms-¹
Force = mass × acceleration
=5kg × (3/4)ms-¹
=15/4 N
= (25-10)/20
= 15/20 = 3/4 ms-¹
Force = mass × acceleration
=5kg × (3/4)ms-¹
=15/4 N
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karraAshish:
wrong
Answered by
14
Heya friend,
Here is the answer-
m= 5kg
u=10m/s
v=25m/s
t=20s
F= ?
F=ma= m(v-u)/t
=5(25-10/20)
=5(15/20)
=15/4 =3.75 N
Force applied = 15/4 N or 3.75N
Note-
u=initial velocity
v=final velocity
t=time
F=Force
m=mass
Hope it helps.....!!!!!!!
Here is the answer-
m= 5kg
u=10m/s
v=25m/s
t=20s
F= ?
F=ma= m(v-u)/t
=5(25-10/20)
=5(15/20)
=15/4 =3.75 N
Force applied = 15/4 N or 3.75N
Note-
u=initial velocity
v=final velocity
t=time
F=Force
m=mass
Hope it helps.....!!!!!!!
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