Question

an object of mass 5kg is moving with a velocity of mpers. A force is applied so that in 15s, it attains a velocity of 25mpers. what is the force applied on the object​

Answer 1

Answer:

5 N

Explanation:

mass=5 kg

u=10 m/s

v=25 m/s

t=15 sec

a=v-u/t

 =25-10/15

 =1 m/s²

F=ma

  =5×1

  =5 N

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Answer 2

Given:

Mass (m) = 5 kg

Final velocity (v) = 25 m/s

Initial velocity (u) = 10 m/s

Time taken (t) = 15 sec

Now,

Using first equation of motion:

$\implies$ $\huge{\boxed{\sf{v = u+at}}}$

We get:

$\implies$ 25 = 10 + (a) (15)

$\implies$ 15 = 15 a

$\implies$ a = 1 m/s²

We know that,

$\boxed{\sf{Force = Mass \times Acceleration}}$

So:

$\implies$ Force = m × a

$\implies$ Force = 5 kg × 1 m/s²

$\implies$ Force = 5 N

Therefore:

Force applied on the object: 5 N