an object of mass 5kg is whirled round in a vertical circal of radius 2m with a constant speed of 6m/s the maximum tensio in the strong is
Answers
Answer:
using centripetal force,
F=mv^2
F=5×2^2
= 20N
Fg=mg
= 5×9.8
49.0N
therefore
max tension=20+49.0=69N
min tension=24-49.0=-25N
I assume the original question intended to ask for tension in a string, rather than a spring (as written). If so, it is clear that the tension becomes negative at the top of the circle, and since one cannot push on a string, the object simply ceases to travel through the circular path. If one tried to do so, the object would fall downward before reaching the top of the circle, and would result in a very large impulse of force at the instant the string becomes taut again.
If, on the other hand, it is a spring that holds the object, it may very well continue on a predictable path, but it is important to know the spring constant to make an accurate prediction of that path. Even then, resonance effects would probably make the tension unpredictable from one rotation to the next
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