Question

An object of mass 6 kg covers a distance of 100 m from it's position of rest in 5 sec.Find force acting on it.

Answer 1

Answer:-

• Distance=100m
• Time=5s

Find velocity

$\\ \sf\longmapsto Velocity=\dfrac{Distance}{Time}$

$\\ \sf\longmapsto Velocity=\dfrac{100}{5}$

$\\ \sf\longmapsto Velocity=20m/s$

Now

• initial velocity=u=0m/s
• Final velocity=v=20m/s
• Time=t=5s
• Mass=m=6kg

We know

$\boxed{\sf Force=\dfrac{m(v-u)}{t}}$

$\\ \sf\longmapsto Force=\dfrac{6(20-0)}{5}$

$\\ \sf\longmapsto Force=\dfrac{6(20)}{5}$

$\\ \sf\longmapsto Force=\dfrac{120}{5}$

$\\ \sf\longmapsto Force=24N$