An object of mass 60 kg gets the velocity of 50 metre per second in 10 seconds from rest . Calculate the required for applied on that object.
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Given:-
•Mass of the object(m)=60kg
•Initial velocity(u)=0 (as it was at rest initially)
•Final velocity(v)=50m/s
•Time(t)=10s
To find:-
•Force applied on the object(F)
Solution:-
By using the first equation of motion we get----
=>v=u+at
=>50=0+a×10
=>50=10a
=>a=50/10
=>a=5m/s²
Thus,acceleration is 5m/s².
Now,by Newton's 2nd law of motion,we know that----
=>F=ma
=>F=60×5
=>F=300N
Thus,the required force is 300N.
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