Physics, asked by deepanshukumardiwaka, 5 hours ago

An object of mass 800 kg is accelerated uniformly from a velocity of 15 m/s to 18 m/s in 6 sec. Find the magnitude of the force exerted on the object.​

Answers

Answered by rajendramali8546
0

Answer:

Initial velocity of the object (u) = 5 m/s

Final velocity of the object (v) = 8 m/s

Mass of the object (m) = 100 kg

Time take by the object to accelerate (t) = 6 s

Initial momentum = mu = 100 × 5

⇒ mu = 500 kg m/s

Final momentum = mv = 100 × 8

⇒ mv = 800 kg m/s

Let us calculate the Force exerted on the object (F)

F = (mv – mu) / t

F = (800 – 500)/6

F = 300 / 6

F = 50 N

Initial momentum of the object is 500 kg m sˆ1.

Final momentum of the object is 800 kg m sˆ1.

Force exerted on the object is 50 N.

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