Question

- An object of mass lookg is accelerated
conformly from a velocity of 5 ms
to ams in 65 Calculate the initial and
final momentum of the object also final
the magnitude of the force exerted
the object .​

Answer 1

Explanation:

Mass of object, m=100kg; initial velocity, u=5ms

Mass of object, m=100kg; initial velocity, u=5ms −1

Mass of object, m=100kg; initial velocity, u=5ms −1 ; final velocity, v=8ms

Mass of object, m=100kg; initial velocity, u=5ms −1 ; final velocity, v=8ms −1

Mass of object, m=100kg; initial velocity, u=5ms −1 ; final velocity, v=8ms −1 ; time, t=6s

Mass of object, m=100kg; initial velocity, u=5ms −1 ; final velocity, v=8ms −1 ; time, t=6sInitial momentum =mu=100×5=500Ns

Mass of object, m=100kg; initial velocity, u=5ms −1 ; final velocity, v=8ms −1 ; time, t=6sInitial momentum =mu=100×5=500NsFinal momentum =mv=100×8=800Ns

Mass of object, m=100kg; initial velocity, u=5ms −1 ; final velocity, v=8ms −1 ; time, t=6sInitial momentum =mu=100×5=500NsFinal momentum =mv=100×8=800NsForce exerted on the object

Mass of object, m=100kg; initial velocity, u=5ms −1 ; final velocity, v=8ms −1 ; time, t=6sInitial momentum =mu=100×5=500NsFinal momentum =mv=100×8=800NsForce exerted on the objectF=

Mass of object, m=100kg; initial velocity, u=5ms −1 ; final velocity, v=8ms −1 ; time, t=6sInitial momentum =mu=100×5=500NsFinal momentum =mv=100×8=800NsForce exerted on the objectF= t

Mass of object, m=100kg; initial velocity, u=5ms −1 ; final velocity, v=8ms −1 ; time, t=6sInitial momentum =mu=100×5=500NsFinal momentum =mv=100×8=800NsForce exerted on the objectF= tmv−mu

Mass of object, m=100kg; initial velocity, u=5ms −1 ; final velocity, v=8ms −1 ; time, t=6sInitial momentum =mu=100×5=500NsFinal momentum =mv=100×8=800NsForce exerted on the objectF= tmv−mu

Mass of object, m=100kg; initial velocity, u=5ms −1 ; final velocity, v=8ms −1 ; time, t=6sInitial momentum =mu=100×5=500NsFinal momentum =mv=100×8=800NsForce exerted on the objectF= tmv−mu =

Mass of object, m=100kg; initial velocity, u=5ms −1 ; final velocity, v=8ms −1 ; time, t=6sInitial momentum =mu=100×5=500NsFinal momentum =mv=100×8=800NsForce exerted on the objectF= tmv−mu = 6

Mass of object, m=100kg; initial velocity, u=5ms −1 ; final velocity, v=8ms −1 ; time, t=6sInitial momentum =mu=100×5=500NsFinal momentum =mv=100×8=800NsForce exerted on the objectF= tmv−mu = 6800−500

Mass of object, m=100kg; initial velocity, u=5ms −1 ; final velocity, v=8ms −1 ; time, t=6sInitial momentum =mu=100×5=500NsFinal momentum =mv=100×8=800NsForce exerted on the objectF= tmv−mu = 6800−500

Mass of object, m=100kg; initial velocity, u=5ms −1 ; final velocity, v=8ms −1 ; time, t=6sInitial momentum =mu=100×5=500NsFinal momentum =mv=100×8=800NsForce exerted on the objectF= tmv−mu = 6800−500 =

Mass of object, m=100kg; initial velocity, u=5ms −1 ; final velocity, v=8ms −1 ; time, t=6sInitial momentum =mu=100×5=500NsFinal momentum =mv=100×8=800NsForce exerted on the objectF= tmv−mu = 6800−500 = 6

Mass of object, m=100kg; initial velocity, u=5ms −1 ; final velocity, v=8ms −1 ; time, t=6sInitial momentum =mu=100×5=500NsFinal momentum =mv=100×8=800NsForce exerted on the objectF= tmv−mu = 6800−500 = 6300

Mass of object, m=100kg; initial velocity, u=5ms −1 ; final velocity, v=8ms −1 ; time, t=6sInitial momentum =mu=100×5=500NsFinal momentum =mv=100×8=800NsForce exerted on the objectF= tmv−mu = 6800−500 = 6300

Mass of object, m=100kg; initial velocity, u=5ms −1 ; final velocity, v=8ms −1 ; time, t=6sInitial momentum =mu=100×5=500NsFinal momentum =mv=100×8=800NsForce exerted on the objectF= tmv−mu = 6800−500 = 6300 =50N

Answer 2

Correct Question:-

• An object of mass 100 kg is accelerated from a velocity of 5m/s to 8m/s in 6 seconds. Calculate, the initial and final velocity of the object and also find the magnitude of the force exerted by the object.

Given:-

• mass of the object:- 100kg.
• initial velocity (u) = 5m/s
• final velocity (v) = 8m/s
• time period (t) = 6 sec.

To find:-

• initial momentum
• final momentum
• force exerted.

Formula to be used up:-

$\underline{\boxed{\sf \ momentum = mass × velocity}}$

$\underline{\boxed{\sf \ force = (mv-mu)/t}}$

Solution:-

$\implies$ $\sf {\: initial \: momentum = mass × u}$

$\implies$ $\sf{\: initial \: momentum = 100 × 5 }$

$\implies$ ${\boxed{\sf \ 500 kg.m/sec.}}$

$\implies$ $\sf{\:final \: momentum = mass × v}$

$\implies$ $\sf{\:final \: momentum = 100 × 8}$

$\implies$ ${\boxed{\sf \ 800 kg.m/s}}$

$\implies$ $\sf {\: force = 800-500/6}$

$\implies$ $\sf {\: force = 300/6 }$

$\implies$ ${\boxed{\sf \ 50 N}}$