An object of mass m at rest is acted ypon by a force f for time t. The kinetic energy of object aftervtime t is
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f = ma
a =f/m
a = dv/dt
dv = adt
By double integrated
V^2 = at^2
Now ke = 1/2mv2=1/2*m *at^2=1/2*f*t2=1/2*f*t^2
a =f/m
a = dv/dt
dv = adt
By double integrated
V^2 = at^2
Now ke = 1/2mv2=1/2*m *at^2=1/2*f*t2=1/2*f*t^2
rishi7586:
please brainlist
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We know that...
Kinetic Energy (K.E) = \frac{1}{2} mv^{2}
Final Velocity = Initial Velocity + Acceleration × Time
Force = Mass × Acceleration
Substituting the above 2 equations...
\frac{F^{2}T^{2}}{2m}
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