An object of mass m drops from rest a little above the surface of Earth for a time t. Ignore the air resistance. After time t, the magnitude of the momentum of the object is
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Given: An object of mass m drops from rest a little above the surface of Earth for a time t.
To find: The magnitude of the momentum of the object after time t.
Solution:
- The linear momentum of a body is the product of the mass and the velocity of the body.
- Momentum is a vector quantity. Its direction is the same as the direction of velocity.
- It is given by the formula,
- Here, p is the momentum, m is the mass and v is the velocity of the body.
- For a freely falling body,
- Here, v is the final velocity, u is the initial velocity of the body, g is the acceleration due to gravity and t is the time taken.
- Since the body is dropped, its initial velocity is zero.
- Hence,
Therefore, the magnitude of the momentum of the object is 10mt kgms⁻¹.
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