Physics, asked by m76652387, 25 days ago

An object of mass m drops from rest a little above the surface of Earth for a time t. Ignore the air resistance. After time t, the magnitude of the momentum of the object is​

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Answered by shruti6437
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Answered by PoojaBurra
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Given: An object of mass m drops from rest a little above the surface of Earth for a time t.

To find: The magnitude of the momentum of the object after time t.

Solution:

  • The linear momentum of a body is the product of the mass and the velocity of the body.
  • Momentum is a vector quantity. Its direction is the same as the direction of velocity.
  • It is given by the formula,

        p = m v

  • Here, p is the momentum, m is the mass and v is the velocity of the body.
  • For a freely falling body,

        v = u + gt

  • Here, v is the final velocity, u is the initial velocity of the body, g is the acceleration due to gravity and t is the time taken.
  • Since the body is dropped, its initial velocity is zero.

        v = 0 + (10ms^{-2}) (t)

           = 10 t

  • Hence,

        p = (m) (10 t)

           = 10mt

Therefore, the magnitude of the momentum of the object is​ 10mt kgms⁻¹.

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