Physics, asked by mbhulkund977, 4 months ago

an object of mass M is dropped from a height h if it strikes the ground with speed root 0.8 GH than work done by air resistance is​

Answers

Answered by nirman95
4

Given:

An object of mass M is dropped from a height h if it strikes the ground with speed √(0.8gh) .

To find:

Work done by air resistance ?

Calculation:

In these type of questions, it is best to apply work energy theorem, which states : the net work done by all the forces will be equal to the change in Kinetic energy of the object.

 \therefore \: W_{gravity} + W_{air \: res.} = \Delta KE

 \implies \: Mgh+ W_{air \: res.} =  \dfrac{1}{2} M {v}^{2}  - 0

 \implies \: Mgh+ W_{air \: res.} =  \dfrac{1}{2} M {( \sqrt{0.8gh} )}^{2}

 \implies \: Mgh+ W_{air \: res.} =  \dfrac{1}{2} M (0.8gh)

 \implies \: Mgh+ W_{air \: res.} =  0.8(Mgh)

 \implies \:  W_{air \: res.} =  0.8(Mgh) - Mgh

 \implies \:  W_{air \: res.}  =  - 0.2(Mgh)

So, net work done by air resistance:

 \boxed{ \bf \:  W_{air \: res.}  =  - 0.2(Mgh)}

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