Physics, asked by lukkaakshayguna, 4 months ago

an object of mass M is dropped from height H.at what height the potential energy of the body is twice that of its kinetic energy

Answers

Answered by shreenath13

0

Answer:

ANSWER

Initial Energy of the body =K.E+P.E

KE

i

=0,PE

i

=mgh

Final Energy KE

f

+PE

f

PE

f

=0

Energy is conserved

Final Energy = Initial Energy

KE

f

=PE

i

=mgh

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