Question

An object of mass m is floating in a liquid of density sigma.If the object is made up of density rough apparent weight of object in liquid is

Answer 1

"Given that,

Mass of object = m

Density of liquid $= \quad \sigma$

Density of object $= \rho$

We know that,

The weight of object in liquid is the difference of the weight of the object and weight of the displaced water.

Let us consider W is the apparent weight of the object in liquid.

W = weight of the object - weight of the displaced water

$W\quad =\quad mg-V\sigma g\quad$

Now, the volume of the displaced water = volume of the object

So, the true weight of the object is $W\quad =\quad mg-\frac { m }{ \rho } \sigma g$

$W\quad =\quad \frac { mg }{ \rho } \left( \rho -\sigma \right)$

Hence, the true weight of the object in liquid is $W\quad =\quad \frac { mg }{ \rho } \left( \rho -\sigma \right)$"

Answer 2

Explanation:

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