Physics, asked by mso, 3 months ago

An object of mass ‘m‘ is kept on the floor of a lift. What will be the apparent weight of the object when the lift moves with a constant speed ‘v’ downwards?

Answers

Answered by sweetisingh1983
0

Answer:

Explanation:

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Answered by nirman95
8

Given:

An object of mass ‘m‘ is kept on the floor of a lift.

To find:

Apparent weight of object when lift moves down with constant velocity "v" ?

Calculation:

Apparent weight is the net reaction force experienced by the object in the lift when the lift accelerates upwards/downwards.

Let's assume that acceleration of lift is "a" and directed downwards.

So, object will experience pseudo-force upwards.

 \therefore \: W_{app} = mg -  f_{pseudo}

 \implies\: W_{app} = mg - ma

  • Since it is travelling with constant velocity downwards, "a" will be zero.

 \implies\: W_{app} = mg - m(0)

 \implies\: W_{app} = mg

So, apparent weight will be equal to weight of the body.

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