An
object
of
mass
‘m‘
is
kept
on
the
floor
of
a
lift.
What
will
be
the
apparent
weight
of
the
object
when
the
lift
moves
with
a
constant
speed
‘v’
downwards?
Answers
Answered by
6
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Explanation:
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Answered by
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Given:
The mass of the object is = m
The lift is moving with a constant velocity in downwards direction = v
To find:
The apparent weight of the object when it is kept on the floor of the lift.
Solution:
The apparent weight can be found out by vector addition of the weight of the object and the other forces acting on the object.
Since the lift moves with a constant velocity, its acceleration = 0
Apparent weight = mg
If the lift had an acceleration a in downward direction then,
Apparent weight must had been = m(g - a)
Therefore Apparent weight of the object will be equal to its weight = mg.
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