an object of mass M is kept on the floor of a lift what will be the Apparent weight of the object when the lift moves from a constant speed V downwards
Answers
Given:
The mass of the object is = M
The lift is moving with a constant velocity in downwards direction = V
To find:
The apparent weight of the object when it is kept on the floor of the lift.
Solution:
The apparent weight can be found out by vector addition of the weight of the object and the other forces acting on the object.
Since the lift moves with a constant velocity, its acceleration = 0
Apparent weight = Mg
If the lift had an acceleration a in downward direction then,
Apparent weight must had been = M(g - a)
Therefore Apparent weight of the object = Mg.
Given:
An object of mass M is kept on the floor of a lift.
To find:
Apparent weight of the object when lift is moving down with constant velocity v ?
Calculation:
First of all , what is APPARENT WEIGHT inside the lift?
- Apparent weight is the the new normal reaction experienced by the person (in the lift), when the lift is accelerated downwards/upwards.
- For example: when lift is being accelerated downwards, the man will experience a pseudo-force upwards, and his normal reaction will be reduced than his weight. So, he will feel somewhat less weight.
- Refer to diagram.
Now, since question says that lift is moving with constant velocity v , the value of "a" = 0 m/s².
So, apparent weight will be equal to weight of the body.