Question

An object of mass m is moving at a velocity v. Find the ratio of its kinetic energy to its  momentum when its speed is doubled​

Answer 1

Answer:

Since, KE/Momentum is directly proportional to V

Therefore, when the speed is doubled, ratio of kinetic energy to its momentum is also doubled.

Explanation:

Given,

Mass = m

Velocity = v

So, KE/ Momentum = (1/2mv²) / (mv)

(R) = v/2

If Velocity is doubled, then,

Ratio of KE/Momentum = [ 1/2m(2v²) / m(2v)]

= [ 1/2m4v² / 2mv]

(R') = v

(R') = 2R

Hope it will help you!!