an object of mass m is projected from the ground with initial speed v0 find the speed at height h
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Given:
Initial speed of the object = v0 m/s
Mass of the object = m kg
To find:
Speed of the object at height h.
Solution:
Using the formula: v²= u² + 2aS
Where v = final velocity,
u =initial velocity,
S is the distance covered,
a is the acceleration.
Here in this case acceleration is in the opposite direction and magnitude = acceleration due to gravity (g)
Putting the values we get:
v² = v0² + 2*(-g)*h
v² = v0² - 2gh
v =√(v0²- 2gh)
The speed at height h = √(v0² -2gh) m/s.
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