an object of mass m is thrown with a velocity u ms-1 at 60degree at the horizontal. the momentum of the object when it was thrown was 20 kgms-1 . Find momentum at the highest point of it's journey
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momentum of object at the highest point of its journey is 10 Kgm/s.
It has given that an object of mass m is thrown with a velocity u m/s at 60° at the horizontal. the momentum of the object when it was thrown was 20 Kgm/s.
we have to find the momentum at the highest point of its journey.
initial momentum = mu = 20 Kgm/s .......(1)
velocity of object at the highest point of its journey is ucos60° ( along x-axis)
the momentum of object at the highest point of its journey = mucos60°
from equation (1) we get,
= mu × (1/2)
= mu/2
= 20/2 = 10 Kgm/s
therefore, momentum of object at the highest point of its journey is 10 Kgm/s.
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