Question

An object of mass m1 moving pd collides with another object of mass m2 at rest and stick to it find the impulse imparted to the second object

Answer 1

Answer:

From the momentum Conservation,

m1v + 0 = (m1+m2)v’

v’ = m1v/(m1+m2) m/s.

 

J = change in momentum ( for second object.)

that is = > Pf – Pi

=> (m2)v’ - m2*0  

=> m1*m2*v/(m1+m2) N-m.

Explanation:

Answer 2

The impulse imparted to the second object is $\dfrac{m_1m_2v_1}{(m_1+m_2)}$.

Explanation:

An object of mass m₁ moving pd collides with another object of mass m₂ at rest and stick to it. Using the conservation of linear momentum as :

$m_1v_1+m_2v_2=(m_1+m_2)V$

V is the common speed of the object after the collision

Here, $v_2=0$ (at rest)

$m_1v_1=(m_1+m_2)V\\\\V=\dfrac{m_1v_1}{(m_1+m_2)}$

The impulse imparted to second object is equal to change is momentum as :

$J=m_2V\\\\J=\dfrac{m_1m_2v_1}{(m_1+m_2)}$

Hence, the impulse imparted to the second object is $\dfrac{m_1m_2v_1}{(m_1+m_2)}$.

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