Question

an object of mass20 kg is moving with a velocity 15 m/s its velocity incresesto 35m/s on applaying this content force contiusly for 5s calculate theaccelaration and calculate the force applid​

Answer 1

Correct question:

An object of mass 20 kg is moving with a velocity 15 m/s, its velocity increases to 35m/s on applying this content force continuosly for 5s.Calculate the acceleration and calculate the force applied.

Required Solution:

Given:

• Mass of the object (m) = 20kg
• Initial velocity (u) = 15m/s
• Final velocity (v) = 35m/s
• Time taken (t) = 5s

To calculate:

• Acceleration (a)
• Force applied (F)

Calculation:

${\underline {\boxed {\large {\sf { Calculating \: acceleration: } }}}}$

We know that,

• ${\underline {\boxed {\large {\sf { a = \dfrac{v-u}{t}} }}}}$

$\sf { ⇢ a = \dfrac{35-15}{5}}$

$\sf { ⇢ a = \dfrac{20}{5}}$

$\boxed{ \sf { ⇢ a = 4m/{s}^{2}} }$

Therefore,acceleration of the object is -4m/s².

[Note : Negative sign implies that it is retardation.]

_______________________________

${\underline {\boxed {\large {\sf { Calculating \: force \: applied:} }}}}$

We know that,

• ${\underline {\boxed {\large {\sf { F = ma} }}}}$

Where,

F = force

m = mass

a = acceleration

$\sf { ⇢ F = 20 \times 4 }$

$\boxed{ \sf { ⇢ F = 80N}}$

Therefore,80N of force is applied on the object.

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Answer 2

Correct version of the question is already given by @HealingPearl.

Mass of particle = 20 kg

Former velocity = 15 m/s

Final velocity = 15 m/s

Time = 5 s

We know,

a = (v - u)/t and F = m × a

a:-

a = (35 m/s - 15 m/s)/(5 s)

$\leadsto$ a = (20 m/s)/(5 s)

$\leadsto$ a = 4 m/s². (I)

F:-

F = ma

$\leadsto$ F = (20 kg)(4 m/s²)

$\leadsto$ F = 80 kg m/s²

$\leadsto$ F = 80 N. (II)