Question

An object of mass50kg having a kinetic energy of 200joule. What would be it's kinetic energy if velocity is increased four times?​

Answer 1

Answer:

200.72J

Explanation:

Mass of the object : 50 kg

Kinetic energy =200J

Velocity=?

Kinetic energy =1/2mv^2

1/2mv^2=200

1/2×50×v^2=200

v^2=200×2/50

v^2=8

v=2√3

When velocity is increased by four times , then

v =2√3×4

v=8√3

Kinetic energy =1/2×50×8√3 =200✓3 J =200×1.7=200.72J