Question

an object of size 10 cm is placed 40 cm away from the converging lens of focal length 60 cm find the position size nature formed ..​

Answer 1

Given :-

Height of object = h = 10 cm

Object distance = u = -40 cm

Focal Length = f = 60 cm

Focal length is positive because image if formed either side of the lens.

By Lens Formula, we know that,

1/v - 1/u = 1/f

1/v - (-1/40) = 1/60

1/v + 1/40 = 1/60

1/v = 1/60 - 1/40

1/v = 4-6/240

v = -120 cm

Again by a relation we know that,

Let the height of image = h'

h'/h = -v/u

h' = -v/u × h

h' = -(-120)/-40 × 10

h' = -30 cm

Hence,

The image distance = v = -120 cm

Height of image = h' = -30 cm

Nature of image = Real, Enlarge and inverted.