Question

an object of size 10cm is placed at a distance of 6cm fram a diverging lense of focal length 10cm.find nature,size and position of the image​

Answer 1

Explanation:

here is your answer with the attachment

Answer 2

Given :

Size of object = 10cm

Distance of object = 6cm

Focal length of lens = 10cm

Type of lens : concave

To Find :

Position, nature and size of the image.

Solution :

❖ Focal length of concave lens is taken negative and that of convex lens is taken positive.

• Distance of image can be calculated by using lens formula$.$

➙ 1/v - 1/u = 1/f

• v denotes distance of image
• u denotes distance of object
• f denotes focal length

By substituting the given values;

➙ 1/v - 1/(-6) = 1/(-10)

➙ 1/v = -1/10 - 1/6

➙ 1/v = (-6 - 10) / 60

➙ 1/v = -16/60

➙ v = -60/16

➙ v = -3.75 cm

♦ Size of image :

➙ m = v/u = h'/h

• h' denotes size of image
• h denotes size of object

➙ (-3.75)/(-6) = h'/10

➙ h' = 0.625 × 10

➙ h' = 6.25 cm

♦ Nature of image :

• Virtual
• Erect
• Small