An object of size 2.0 cm is placed at a distance of 20.0 cm in front of a concave mirror of focal length 10.0 cm . At what distance should a screen be placed in order to obtain a clear focussed image of the object?
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Height of the object =2 cm
U(object distance) = -15 as u is always negative
F = -10 (as it is always negative for concave miror and lens )
1/F =1/v + 1/u
-1/10 = 1/v + (-1/15)
-1/10 +1/15 =v
-3+2/30 =v
V=-30cm
Hi/Ho = - V/U
Hi /2 = -(-30/15)
Hi =-30×2÷15
Hi =-4cm (Real and inverted)
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