Question

An object of size 4 cm is placed at the centre of curvature of a concave mirror, at a distance 20 cm from the pole. 1. What is the size of the image? 2. What is the image distance from the pole? 3. Find the magnification of the mirror. 4. What is the nature of the image?


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Answer 1

Answer:

Given:-

• Object height ,ho = 4cm

• Object distance ,u = 20 cm

To Find:-

1. What is the size of the image
2. What is the image distance from the pole
3. Find the magnification of the mirror.
4. What is the nature of the image

Solution:-

Before going to Solve this problems you should know about the images formed by concave mirror .

If the object is placed at the Centre of Curvature the image is formed on the centre of Curvature . It means that the image is formed at the same position where the object is placed and the height of image is also same as the height of object.

(1)

•What is the size of the image

The image size is same as the size of object because the object is placed on the Centre of Curvature . Therefore, the image height is 4 cm.

(2)

• What is the image distance from the pole

The image distance from the pole is same as the object is placed from the pole . It means that the image distance is 20 cm from the pole.

(3)

• Find the magnification of the mirror.

As we know that Magnification is defined as the ratio of image to the ratio of height of object.

• m = hi/ho

Substitute the value we get

→ m = 4/4

→ m = 1

Therefore, the magnification is 1 .

(4)

•What is the nature of the image

The nature of the image is real , same size and inverted .

Answer 2

Answer:

1. What is the size of the image?

Ans:- 4 cm

2. What is the image distance from the pole?

Ans:- 20 cm

3. Find the magnification of the mirror.

Ans:- m= -v/u

=> m = -20/-20

=> m = 1

4. What is the nature of the image?

Ans:- Real , Inverted same size .