Question

an object of size 4 cm, of is placed in front of converging mirror of radius 30 cm at a distance of 20 cm. find the position and nature of the image also draw a scale arrange ray ​

Answer 1

Answer:

The position of the image is at -30 cm and the image is the inverted, real, and the same size.

Explanation:

Given:

Object height = 4 cm

Radius of curvature = -30 m

Object distance = 20 cm

The focal length of the mirror $f = \frac{R}{2} = -15 cm$

From the mirror equation,

$\frac{1}{v} + \frac{1}{u} = \frac{1}{f} \\\frac{1}{v} + \frac{1}{-30} = \frac{1}{-15} \\\\v = -30 cm$

The magnification,

$M = \frac{v}{u} \\M = \frac{-30}{-30} = 1$

Hence the image is inverted, real, and of the same size equal to 4 cm.