Question

An object of size 5.0 cm is kept perpendicular at tge principal axis of a cincave lens of focal length 15.0 cm. The image of the object id formed at a distance of 10.0 cm from the lens. determine the following :- (1) The distance of the object from the lens and (2) Nature and size of the image .​

Answer 1

Explanation:

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Answer 2

Explanation:

Given that,

Size of the object, h = 5 cm

Focal length of the concave lens, f = -15 cm

Image distance, v = 10 cm

(1) Let u is the object distance. Using lens formula as :

$\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}$

$\dfrac{1}{v}+\dfrac{1}{f}=\dfrac{1}{u}$

$\dfrac{1}{3}+\dfrac{1}{-15}=\dfrac{1}{u}$

$\dfrac{1}{10}+\dfrac{1}{-15}=\dfrac{1}{u}$

u = 30 cm

(2) Using the magnification formula as :

$m=\dfrac{h}{h'}=\dfrac{v}{u}$

h' is the size of image

$\dfrac{5}{h'}=\dfrac{10}{30}$

h' = 15 cm

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Lens formula

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