an object of size 5 cm is placed at 30 cm in front of concave mirror focal length is 15 cm what is the distance of human and the size of image
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As per question, size of a object, h = +5 cm;
focal length of the concave mirror, f = -15 cm
and object distance, u = -30 cm
1/v + 1/u = 1/f, hence, we have
1/v = 1/f - 1/u = 1/(-15)-1/(-30)
= -1/15+1/30 = -1/30
v = -30 cm
m = h'/h = -v/u
size of the image, h' = -v/u × h
= (-30)/(-30)×5
= -5cm
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formula related to focal length f, object-to-mirror distance u and image-to-mirror distance v is given by
solving the above eqn for v, we get v = 30 cm
(1) image is formed at a distance 30 cm from concave mirror
(2) Since image distance and object distance are same ( both are at 2F), magnification = 1
Image and object are same size.
(3) image is real
(4) image is inverted
solving the above eqn for v, we get v = 30 cm
(1) image is formed at a distance 30 cm from concave mirror
(2) Since image distance and object distance are same ( both are at 2F), magnification = 1
Image and object are same size.
(3) image is real
(4) image is inverted
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