Question

An object of size 5 cm is placed at a distance 15 centimetre from a concave lens of focal length 10cm find the size and the position of the image formed.

Please amswer step-by-step​

Answer 1

Step-by-step explanation:

answr

An object of 5cm tall is placed at a distance of 10cm from a concave mirror of radius of curvature 30cm

i) Find the nature, position and size of the image

ii) Draw the ray diagram to represent the above case.

Given: An object of 5cm tall is placed at a distance of 10cm from a concave mirror of radius of curvature 30cm

To find: the nature, position and size of the image and draw the ray diagram to represent the above case.

Solution:

According to the given criteria,

Let height of the image be h

i

and

Height of the object, h

o

=5cm

Object distance, u=−10cm

Radius of curvature, R=−30cm

We know, focal length, f=

2

R

=

2

30

=−15cm

Now applying mirror formula, we get

f

1

=

v

1

+

u

1

⟹

v

1

=

f

1

−

u

1

⟹

v

1

=

−15

1

−

−10

1

⟹

v

1

=

150

−10+15

=

150

5

⟹v=30cm

Position of the image is behind the mirror at the distance of 30 cm

Magnification, m=−

u

v

=

h

o

h

i

⟹−

−10

30

=

5

h

i

⟹h

i

=3×5=15cm

Nature of the image formed: virtual, erect (as magnification is positive) and enlarged.

Answer 2

Answer:

The negative sign of the height of the image and the magnification shows that the image is erect and vertual. and size of image is very large.

The positive sign of image distance shows that image is formed at 30 CM on the other side of lens.

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