Question

an object of size 5cm is placed at 25cm in front of a concave mirror of focal length 10cm.At what distance from the mirror should a screen be placed, so that a sharp focussed Image can be obtained?Find the size and nature of the image.​

Answer 1

Answer:

hi = 1.43

Explanation:

Given : u=−25 cm f=−10 cm ho =5 cm

Using 1/v - 1/u = 1/f

Or,

1 /v − 1 /(−25) = 1 /(−10)

⟹ v=−7.14 cm

Height of image

ho /hi= v/ u

Or,

hi/5 = −25/−7.14

⟹ hi =1.43

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