an object of size 5cm is placed at a distance of 25cm from the pole of a cancave mirror of radius of curvature 30cm calculate the distance and size of the image so formed what will be the nature of the image
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f=r/2
f=30/2=15
h=5cm
u=-25cm
1/f=1/u+1/v
1/15=1/-25+1/v
1/v=1/15-1/-25
1/v=1/15+1/25
LCM=75
1/v=1×5/15×5+1×3/25×3
1/v=5/75+3/75
1/v=5+3/75
1/v=8/75
v=75/8
h'/h=-v/u
h'=-v/u×h
h'=-v/-25×5
h'=v/5
h'=75/8×5
h'=15/8
f=30/2=15
h=5cm
u=-25cm
1/f=1/u+1/v
1/15=1/-25+1/v
1/v=1/15-1/-25
1/v=1/15+1/25
LCM=75
1/v=1×5/15×5+1×3/25×3
1/v=5/75+3/75
1/v=5+3/75
1/v=8/75
v=75/8
h'/h=-v/u
h'=-v/u×h
h'=-v/-25×5
h'=v/5
h'=75/8×5
h'=15/8
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