An object of size 5cm is placed in front of a concave mirror at a distance of 25 cm .The focal length of the mirror is 15 cm
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Answer:
Given : u=−25 cm f=−10 cm h o=5 cm
Using 1/v − u/1= 1/f
Or 1/v − 1/(−25) =1/ (−10)
⟹ v=−7.14 cm
Height of image hi/ho=v/u
Or hi/5=−7.14/-25
⟹ hi=1.43
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