Question

An object of size 7.0 cm is placed at 27 cm in front of a concave mirror of focal length 18 cm. At what distance from the mirror should a screen be placed so that a sharp focussed image can be obtained? Find the nature and size of image

Answer 1

The screen should be placed far away from the mirror more than the object...the nature would be real or virtual, upright are inverted and diminished or enlarged in this case the image would be real, upright and enlarged because the distance of the screen is really far away from the mirror...

Answer 2

$\huge\mathfrak{Bonjour!!}$

$\huge\fcolorbox{black}{aqua}{Answer:-}$

⛄ ɢɪᴠᴇɴ,

ᴏʙᴊᴇᴄᴛ ᴅɪsᴛᴀɴᴄᴇ, ᴜ = -27 ᴄᴍ.

★ ᴏʙᴊᴇᴄᴛ ʜᴇɪɢʜᴛ, ʜ = 7 ᴄᴍ.

★ ғᴏᴄᴀʟ ʟᴇɴɢᴛʜ, ғ = -18 ᴄᴍ.

★ ᴀs ᴘᴇʀ ᴛʜᴇ ᴍɪʀʀᴏʀ ғᴏʀᴍᴜʟᴀ,

1/ᴜ + 1/ᴠ = 1/ғ

=) 1/ᴠ = 1/ғ - 1/ᴜ = -1/18 + 1/27 = -1/54

=) ᴠ = -54 ᴄᴍ.

ᴛʜᴇ sᴄʀᴇᴇɴ sʜᴏᴜʟᴅ ʙᴇ ᴘʟᴀᴄᴇᴅ ᴀᴛ ᴀ ᴅɪsᴛᴀɴᴄᴇ ᴏғ 54 ᴄᴍ ɪɴ ғʀᴏɴᴛ ᴏғ ᴛʜᴇ ɢɪᴠᴇɴ ᴍɪʀʀᴏʀ.

ᴍᴀɢɴɪғɪᴄᴀᴛɪᴏɴ, ᴍ = ɪᴍᴀɢᴇ ᴅɪsᴛᴀɴᴄᴇ/ᴏʙᴊᴇᴄᴛ ᴅɪsᴛᴀɴᴄᴇ = -54/27 = -2

ᴛʜᴇ ɴᴇɢᴀᴛɪᴠᴇ ᴠᴀʟᴜᴇ ᴏғ ᴍᴀɢɴɪғɪᴄᴀᴛɪᴏɴ ɪɴᴅɪᴄᴀᴛᴇs ᴛʜᴀᴛ ᴛʜᴇ ɪᴍᴀɢᴇ ғᴏʀᴍᴇᴅ ɪs ʀᴇᴀʟ.

ᴍᴀɢɴɪғɪᴄᴀᴛɪᴏɴ, ᴍ = ʜᴇɪɢʜᴛ ᴏғ ᴛʜᴇ ɪᴍᴀɢᴇ/ʜᴇɪɢʜᴛ ᴏғ ᴛʜᴇ ᴏʙᴊᴇᴄᴛ = ʜ'/ʜ

ʜ' = 7 × (-2) = -14 ᴄᴍ.

ᴛʜᴇ ɴᴇɢᴀᴛɪᴠᴇ ᴠᴀʟᴜᴇ ᴏғ ᴛʜᴇ ɪᴍᴀɢᴇ ʜᴇɪɢʜᴛ ɪɴᴅɪᴄᴀᴛᴇs ᴛʜᴀᴛ ᴛʜᴇ ɪᴍᴀɢᴇ ғᴏʀᴍᴇᴅ ɪs ɪɴᴠᴇʀᴛᴇᴅ.

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