an object of size 7.0cm is placed at 27 cm in front of a concave mirror of radius of curvature 32cm . at what distance from the mirror should a screen be placed, so that a sharp focussed image can be obtained ? find the size and the nature of the image
Answers
Answered by
3
Explanation:
Mirror formula :
v
1
+
u
1
=
f
1
...........(1)
So, u=−27cm
Concave mirror have negative focal length.
f=−18cm
Putting the values in (1),
v
1
+
−27
1
=
−18
1
We get , v=−54cm
Also,
Magnification =
h
1
h
2
=
u
−v
7.0
h
2
=−
−27
−54
h
2
=−14.0cm
Image will be real and inverted and will be of size 14 cm.
Answered by
6
Answer:
Mirror formula :
v
1
+
u
1
=
f
1
...........(1)
So, u=−27cm
Concave mirror have negative focal length.
f=−18cm
Putting the values in (1),
v
1
+
−27
1
=
−18
1
We get , v=−54cm
Also,
Magnification =
h
1
h
2
=
u
−v
7.0
h
2
=−
−27
−54
h
2
=−14.0cm
Image will be real and inverted and will be of size 14 cm.
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