An object of size 7.5 cm is kept at a distance of 35 cm from a convex lens of
focal length 15 cm. Choose a suitable scale to locate the position, nature and size of
the image formed by the lens.
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Given:
An object of size 7.5 cm is kept at a distance of 35 cm from a convex lens of focal length 15 cm.
To find:
Choose a suitable scale to locate the position, nature and size of the image formed by the lens.
Solution:
From given, we have,
Object height = h = 7.5 cm
Object distance = u = -35 cm
Focal length = f = -15 cm
we use the mirror formula,
1/f = 1/u + 1/v
-1/15 = -1/35 + 1/v
1/v = 1/35 - 1/15
1/v = -4/105
v = -26.25 cm
Magnification, m = -v/u = - (-26.25)/(-35) = - 0.75
Image size = h' = -vh/u = - (-26.25)(7.5)/(-35) = - 5.625 cm
As v is negative, so a real, inverted image of height 5.625 cm is formed at a distance of 26.25 cm in front of the mirror.
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