An object of size. 7cm is placed at 27 cm in front of a concave mirror of focal length 18 cm . at what distance from the mirror should a screen be placed, so that a sharp focused image can be obtained? find the size and the nature of the image. please help me with a correct answer.
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(1/v)+(1/u)=1/f
(1/v)+(-1/27)=(-1/18)
1/v=(-1/18)-(-1/27)
1/v=(1/27)-(1/18)
1/v=-1/54
v=-54
screen should be placed 54cm away from the mirror on object size
image is real n inverted
m=(-v/u)
m=h'/h
so (-v/u)=(h'/h)
-(-54/-27)=h'/7
-54/27=h'/7
-2=h'/7
h'=7 (-2)
h'=-14
so the image will be inverted and of height 14cm
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