Question

An object of specific gravity p is hung from a massless string. The tension in string is T. The object is
immersed in water so that one half of its volume is submerged. The new tension in the string is​

Answer 1

If The Tension is t in the Massless string Also its Volume decreases By Half So That the tension is Also Decrrases By Half...........

Answer 2

The new tension of the string is - T( 2s-1/2s)

Let the volume of body be = V

Let the initial tention in string = T

New tension in the string = T'

Buoyant force = F

When the object is in air = T = svg

After body is immersed in liquid - Weight of body - Buoyant force

= svg - 1.v/2g = T'

vg ( s - 1/2) = T'

Svg ( 2s/s -1/s) = T'

T( 2s-1/2s) = T'

Therefore, the new tension in the string is T( 2s-1/2s).