Question

an object of tenth centimetres in length is placed at a distance of 40 centimetres in front of a convex lens of radius of curvature 30cm.find the position of image​

Answer 1

Explanation:

Given,

Object distance, u = - 40 cm

Focal length = 1/2 of radius of curvature

ie. f = +15 cm

Image distance, v =?

We have,

( 1/v - 1/u = 1/f )

:. 1/v - 1/-40 = 1/15

:. 1/v = 1/15 + 1/-40

:. 1/v = (- 40 + 15) / -600

:. 1/v = - 25/-600 = 1/24

:. V = + 24 cm.

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